3x-12/x^2-3x-4

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Solution for 3x-12/x^2-3x-4 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-(3*x)-(12/(x^2))-4 = 0

3*x-3*x-12*x^-2-4 = 0

-12*x^-2 = 4 // : -12

x^-2 = -1/3

-2 < 0

1/(x^2) = -1/3 // * x^2

1 = -1/3*x^2 // : -1/3

-3 = x^2

x belongs to the empty set

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